perimeter of rectangle field is 2400 if the length is increased by 10%and breadth is decreased by20% we get the same perimeter find the length and breadth
Answers
Step-by-step explanation:
Let the length of the rectangle field be l
Let the breadth of the rectangle field be b
We know that the perimeter of a rectangle = 2(l + b)
Therefore,
2(l + b) = 2400
l + b = 1200
The length is increased by 10%,
New length = l + (l * 10/100) = 11l/10
The breadth is decreased by 20%
New breadth = b - (b * 20/100) = 4b/5
New perimeter = 2(11l/10 + 4b/5) = 2[(11l + 8b)/10] = (11l + 8b)/5
According,
If we increase the length by 10% and the breadth is decreased by 20% then we get the original perimeter only
(11l + 8b)/5 = 2400
11l + 8b = 12000
Multiplying 8 on both sides on the equation l + b = 1200
8l + 8b = 9600
Subracting 8l + 8b = 9600 from 11l + 8b = 12000
11l + 8b - 8l - 8b = 12000 - 9600
3l = 2400
l = 800 m
Subtisute l = 800 m in the equation 8l + 8b = 9600
6400 + 8b = 9600
8b = 3200
b = 400 m