Question

perimeter of rectangle is 120 cm if breath of the rectangle is 14 cm find its length and area of rectangle​

Answer 1

Answer:

length = 46cm

Step-by-step explanation:

I hope my answer is correct ☺️

Answer 2

Given : The Perimeter of Rectangle is 120 cm & the Breadth of Rectangle is 14 cm .

Exigency to find : Length and Area of Rectangle .

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❍ Let's Consider the Length of Rectangle be x cm .

⠀⠀Finding Length of Rectangle :

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{Perimeter _{(Rectangle)} \:: 2( l + b) }\bigg\rgroup$

⠀⠀Here l is the Length of Rectangle & b is the Breadth of Rectangle & we know the Perimeter of Rectangle is 120 cm

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \longmapsto \sf 120 = 2( x + 14 )$

$\qquad \longmapsto \sf \cancel {\dfrac{120}{2}} = ( x + 14 )$

$\qquad \longmapsto \sf 60 = ( x + 14 )$

$\qquad \longmapsto \sf 60 - 14 = x$

$\qquad \longmapsto \frak{\underline{\purple{\:x = 46 cm }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Length \:of\:Rectangle \:is\:\bf{46\:cm}}}}$

⠀⠀Finding Area of Rectangle :

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{ Area_{(Rectangle)} \:: l \times b }\bigg\rgroup$

⠀⠀Here l is the Length of Rectangle & b is the Breadth of Rectangle

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \longmapsto \sf Area = 46 \times 14$

$\qquad \longmapsto \frak{\underline{\purple{\:Area = 644 cm^2 }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Area \:of\:Rectangle \:is\:\bf{644\:cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\qquad \leadsto \sf Area_{(Rectangle)} = Length \times Breadth$

$\qquad \leadsto \sf Perimeter _{(Rectangle)} = 2 (Length + Breadth)$

$\qquad \leadsto \sf Area_{(Square)} = Side \times Side$

$\qquad \leadsto \sf Perimeter _{(Square)} = 4 \times Side$

$\qquad \leadsto \sf Area_{(Trapezium)} = \dfrac{1}{2} \times Height \times (a + b )$

$\qquad \leadsto \sf Area_{(Parallelogram)} = Base \times Height$

$\qquad \leadsto \sf Area_{(Triangle)} = \dfrac{1}{2} \times Base \times Height$

$\qquad \leadsto \sf Area_{(Rhombus)} = \dfrac{1}{2} \times Diagonal _{1}\times Diagonal_{2}$

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