Question

perimeter of rectangle is 180 metre and its length is 10 metre more than its width find the length and with the answer NCERT solution​

Answer 1

Answer:

perimeter of rectangle= 180

let the width of a rectangle =X metre

length of rectangle =X + 10

perimeter of rectangle =2(l+b)

180=2(x+x+10)

180 =2(2x+10)

180/2=2x+10

90-10=2x

80/2=x

40=x

the width of the rectangle is 40 metre

and the length of rectangle is 50 meter

Explanation:

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Answer 2

GIVEN :

Perimeter of rectangle = 180 metre

Length is 10 metre more than its width.

TO FIND :

Length of rectangle

FORMULA USED :

Perimeter = sum of all sides

perimeter of rectangle = sum of all sides of rectangle

we know that , opposite sides of rectangle are equal.

Therefore :-

$= > perimeter \: of \: rectangle \: = l + l + b + b$

$= > perimeter \: of \: rectangle \: =2 l +2 b$

$= > perimeter \: of \: rectangle \: = 2(l + b)$

therefore , FORMULA of perimeter of rectangle => 2(l + b)

where :- l = length and b = breadth/ width

SOLUTION :

⟹ Length is 10 metre more than its width

⟹ Let width be X

⟹ therefore length = X + 10 ( because it is given that Length is 10 metre more than its width)

Perimeter of rectangle = 180 metre. ( given)

Now According to the question =>

$⟹2(l + b) = 180$

put l = X + 10 and b = x

$⟹2(x + 10 + x) = 180$

$⟹2(2x + 10) = 180$

$⟹2 \times 2(x + 5) = 180$

$⟹x + 5 = \frac{180}{4}$

$⟹x + 5 = 45$

$⟹x = 45 - 5$

$⟹x = 40$

Therefore width/breadth(X) = 40 metres

Therefore Length = X + 10

$⟹l \: = 40 + 10$

$⟹l = 50m$

Therefore , Length = 50 metres

ANSWER =

Length of rectangle = 50 metres

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More Formulae related to rectangle

=>

1. perimeter of rectangle = 2(l +b)

2. Area of rectangle = l × b

where :- l = length and b = breadth