Question

perimeter of rectangle is 62 cm. length is(2x-1) and breadth is (x+1) find the value of x
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Answer 1

Answer:

$perimeter = 2(l + b) \\ \\ 62 = 2(2x - 1 + x + 1) \\ \\ \frac{62}{2} = 3x \\ \\ 3x = 31 \\ \\ x = \frac{31}{3}$

Answer 2

GIVEN:

Perimeter of the rectangle = 62 cm

Length = (2x-1) cm

Breadth = (x+1) cm

TO FIND:

The value of 'X'

SOLUTION:

Formula for perimeter of a rectangle is:-

==> 2(length + breadth)

Since, length = (2x-1) cm and Breadth = (x+1) cm

Perimeter of the rectangle = 2 [(2x-1)+(x+1)]

= 2 [2x - 1 + x + 1]

= 2 [3x]

= 6x

It's given that perimeter is 62 cm.

This means that, 6x = 62

==> x = 62/6

==> x = 10.33 cm

∴ Value of x = 10.33 cm

ANSWER: X = 10.33 cm

Additional Information

Since, the value of X is found, we can now find the value of length and breadth.

Length = 2x-1 = 2(10.33) -1 = 19.66 cm

Breadth = x+1 = 10.33 + 1 = 11.33 cm