Question

perimeter of rectangle is 76 meter the length is two more than twice the width find the dimensions​

Answer 1

Perimeter is 76 m
Let the breadth be x
Length is x+2
2(x+x+2)=76
4x + 4= 76
x=18
Breadth is 18 m
Length is 20 m

Answer 2

⚝ Given Information :-

Perimeter of rectangle is 76 meter the length is two more than twice the width find the dimensions ?

• Perimeter of rectangle = 76 m
• Length of rectangle = 2x + 2
• Let the breadth/width of rectangle = x
• Dimensions = ?

⚝ Formula used :-

★ Perimeter of rectangle = 2(l + b) ★

Where,

• L = Length of rectangle
• B = Breadth of rectangle

⚝ Putting all values :-

➦ 76 = (2x + 2 + x)

➦ 76 = 2(3x + 2)

➦ 76 = 6x + 4

➦ 76 - 4 = 6x

➦ 72 = 6x

➦ 72/6 = x

➦ 12 = x

Now,

• Width = 12 m

• Length = 2x + 2

ㅤㅤㅤ = 2(12) + 2

ㅤㅤㅤㅤ = 24 + 2

ㅤㅤㅤㅤ = 26 m

Henceforth,

• Length of rectangle is 26 m.
• Breadth of rectangle is 12 m.

⚝ Check :-

Put the values of length and breadth in the formula :

★ Perimeter of rectangle = 2(l + b) ★

➦ 76 = 2(26 + 12)

➦ 76 = 2(38)

➦ 76 = 76

Thus, both sides are equal / same.

Hence, Solution is checked !