Question

Perimeter of rectangle is 80 cm the length of rectangle is 1 cm more than two time of the breadth what is the length

Answer 1

Given :

• Perimeter of Rectangle is 80 cm .
• Length of Rectangle is 1 cm more than 2 times of the breadth .

To Find :

• Length of Rectangle .

Solution :

$\longmapsto\tt{Let\:Breadth\:of\:rectangle\:be=x}$

As Given that length of Rectangle is 1 cm more than 2 times of the breadth . So ,

$\longmapsto\tt{Length=2x+1}$

Using Formula :

$\longmapsto\tt\boxed{Perimeter\:of\:Rectangle=2(l+b)}$

Putting Values :

$\longmapsto\tt{80=2(2x+1+x)}$

$\longmapsto\tt{\cancel\dfrac{80}{2}=3x+1}$

$\longmapsto\tt{40=3x+1}$

$\longmapsto\tt{40-1=3x}$

$\longmapsto\tt{39=3x}$

$\longmapsto\tt{x=\cancel\dfrac{39}{3}}$

$\longmapsto\tt\bf{x=13}$

Value of x is 13 ..

Therefore :

$\longmapsto\tt{Length\:of\:Rectangle=2(13)+1}$

$\longmapsto\tt{26+1}$

$\longmapsto\tt\bf{27\:cm}$

Answer 2

Given :-

• Perimeter of rectangle is 80 cm the length of rectangle is 1 cm more than two times of the breadth what is the length.

To find :-

• Length of rectangle

Solution :-

• Perimeter of rectangle = 80 cm

Let the breadth be x

• The length of rectangle is 1 cm more than two times of the breadth

• Length = 2x + 1

According to question

→ Perimeter of rectangle = 80cm

→ 2(l + b) = 80cm

→ 2(2x + 1 + x) = 80

→ (3x + 1) = 80/2

→ 3x + 1 = 40

→ 3x = 40 - 1

→ 3x = 39

→ x = 39/3

→ x = 13 cm

Hence,

• The value of x is 13cm

Therefore,

• Breadth of rectangle = x = 13cm

• Length of rectangle = 2x + 1 = 2×13 + 1 = 27 cm