perimeter of rectangle is1728 and breadth is 48 find the length
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Perimeter of rectangle = 1728
Breadth of rectangle =48
Let length of rectangle be x .
A/Q
2(48+x)=1728
96+2x=1728
2x=1728-96
2x=1632
x=1632/2
x=816
Hence, length of rectangle is 816.
Answered by
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The perimeter of rectangle = 1728
and the breadth is = 48
therefore,
perimeter of rectangle = 2(l+b)
breadth of rectangle = 2(l+48) = 1728
2l+96=1728
2l = 1728-96
l = 1632/2
l = 816
hence, the length of rectangle is 816..
Hope this answer help you!
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