Math, asked by swaritpathak2009, 17 days ago

perimeter of rectangle whose area is 56cm² and lenght 8m (Give me answer fast)​

Answers

Answered by sadafansari8312
0

Answer:

Area of rectangle= 56

length×breadth=56

8× breadth=56

breadth=7

breadth= 7/10 m^2

Answered by gausia8080
0

Answer:

30m

Step-by-step explanation:

Given data:

  • Area of a rectangle =56m^{2}
  • Length =8m
  • As we know, Area of a rectangle =length\times breadth
  • On substituting the values, we get

56=8\times breadth

breadth=7

  • Perimeter of a rectangle =2(length+breadth)
  • On substituting the values, we get

=2(8+7)\\

=2(15)

=30m

Hence, perimeter of the rectangle =30m

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