Question

perimeter of rectangle whose length is 20/3 and 9/2breath please tell the answer I want to check​

Answer 1

Answer:

Perimeter of a rectangle= 2(l+b)

So,

2(20/3 + 9/2)

2×67/6 = 67/2

So, answer is 67/2

Answer 2

Question:-

What is the perimeter of the rectangle whose length is $\frac{20}{3}$and breadth is $\frac{9}{2}$

Solution:-

Given,

Length of rectangle = $\frac{20}{3}$

Breadth of rectangle = $\frac{9}{2}$

We have,

Perimeter of rectangle is 2(length+Breadth)

So, Perimeter =

$2( \frac{20}{3} + \frac{9}{2} )$

LCM = 2×3 = 6

So,

$2 \times ( \frac{20 \times 2}{3 \times 2} + \frac{9 \times 3}{2 \times 3} )$

$2 \times ( \frac{40}{6} + \frac{27}{6} )$

$2 \times ( \frac{40 + 27}{6} )$

$2 \times ( \frac{67}{6} )$

$= > \frac{67}{3}$

Perimeter of rectangle is $\frac{67}{3}$ cm