Question

perimeter of rectangle whose length is 40 whole 2/3 and breadth is 19 whole 1/2​

Answer 1

$\huge\tt\purple{Answer:}$

$= length = 40\frac{2}{3} = \frac{122}{ 3} \\ = breadh = 19\frac{1}{2} = \frac{39}{2}$

Perimeter = 2(l+b)

$= 2( \frac{122}{3} + \frac{39}{2})$

$= 2( \frac{224 + 117}{6} )$

$= \frac{341}{6} \times 2$

$= \frac{341}{3}$

=113.66666667 cm