Math, asked by rajpatelrajveerpatel, 4 months ago

Perimeter of rectangle with length 5a and breadth 13b isRequired to answer. Single choice.

(1 Point)

a) 2 x 18ab

b) 36ab

c) 10 a + 26 b

d) 10 a + 13b

Answers

Answered by SkundKumar
0

Answer:

B) 36ab is the correct answer....

Step-by-step explanation:

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Answered by Anonymous
5

Correct Question-:

  • Perimeter of rectangle with length 5a and breadth 13b .

AnswEr-:

  • \underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 10a + 26b }}}}}

Explanation-:

Given-:

  • Length of Rectangle = 5a .
  • Breadth of Rectangle = 13 b

Figure related to the question-:

\setlength{\unitlength}{1cm}\begin{picture}(0,0)\thicklines\multiput(0,0)(5,0){2}{\line(0,1){3}}\multiput(0,0)(0,3){2}{\line(1,0){5}}\put(0.03,0.02){\framebox(0.25,0.25)}\put(0.03,2.75){\framebox(0.25,0.25)}\put(4.74,2.75){\framebox(0.25,0.25)}\put(4.74,0.02){\framebox(0.25,0.25)}\multiput(2.1,-0.7)(0,4.2){2}{\sf\large 5a}\multiput(-1.4,1.4)(6.8,0){2}{\sf\large 13b}\put(-0.5,-0.4){\bf A}\put(-0.5,3.2){\bf D}\put(5.3,-0.4){\bf B}\put(5.3,3.2){\bf C}\end{picture}

To Find -:

  • Perimeter of Rectangle.

Now ,

  • \underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 2(Length+ breadth)}}}}}

Here ,

  • Length of Rectangle = 5a .
  • Breadth of Rectangle = 13 b

Now ,

  • \implies {\large{\sf{Perimeter _{Rectangle}= 2(5a +13b)}}}
  • \implies {\large{\sf{Perimeter _{Rectangle}= 10a + 26b }}}

Therefore,

  • \underline{\boxed{\star{\sf{\purple{Perimeter \:of \:Rectangle \:: \: 10a + 26b }}}}}

Hence ,

  • \underline{\boxed{\star{\sf{\purple{The\:option\:C\:or\:10a+26b\:is\:correct. }}}}}

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