Perimeter of rectangular park 40 m, ratio of thier length & wide be 2:5 . then find its area .
Answers
Solution
Given :-
- Perimeter of rectangular park 40 m
- ratio of thier length & wide be 2:5
Find :-
- Its Area
Explanation
Let,
- Length ve = x
- Length ve = xWide be = y
Case 1.
==> x : y = 2:5
==> x/y = 2/5
==> 5x - 2y = 0__________(1)
Case 2.
==> perimeter of rectangular park = 40
==> 2×(x + y) = 40
==> x + y = 40/2
==> x + y = 20__________(2)
Multiply by 2 in equ(2)
==> 2x + 2y = 40________(3)
sum equ(1) & equ(3)
==> 5x + 2x = 40
==> 7x = 40
==> x = 40/7
==> x = 40/7 m
keep in equ(1)
==> 5 × 40/7 - 2y = 0
==> 2y = 200/7
==> y = 200/14
==> y = 100/7
Now, calculate area
==> Area of rectangular park = Length × wide
==> Area of rectangular park = 40/7 × 100/7
==> Area of rectangular park = 4000/49
==> Area of rectangular park = 81.63 m²
_______________
Answer:
let x be the common multiple
length = 2x
breadth = 5x
perimeter = 40
let's find the value of x
perimeter = 2 ( length × breadth )
40 = 2 ( 2x + 5x )
40 = 2 × 7x
40/2 = 7x
20 = 7x
20/7 = x
therefore
length = 2× 20/7
= 40/7
breadth = 5× 20/7
= 100/7
we have asked to find out area
Area of rectangular park = length × breadth
= 40/7 × 100/7
= 4000/ 49 m