Question

perimeter of rhombus is 100 M and its diagonal is 40 metre find the area of Rhombus

Answer 1

Hey

Perimeter of rhombus=4*side

So each side=(100/4)m =25cm

And we know that in a rhombus diagonal divides rhombus in two equilateral triangle.

Area of one triangle:- s=(25+25+40)/2 =45

So area=
$\sqrt{} (s(s-a)(s-b)(s-c))$
$\sqrt{} (45(45-40)(45-25)(45-25)$
=
$300 {m}^{2}$


=》So total area is (300*2)m^2=600m^2

Answer 2

Answer:

Step-by-step explanation:

Perimeter of rhombus=4*side

So each side=(100/4)m =25cm

And we know that in a rhombus diagonal divides rhombus in two equilateral triangle.

Area of one triangle:- s=(25+25+40)/2 =45

So area=

=

=》So total area is (300*2)m^2=600m^2

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