Question

perimeter of rhombus is 68,IF PR=30,then find QS,.​

Answer 1

perimeter of Rhombus = 4a units.

68= 4a

a=17 cm

using pythagoras theorem, with hypotenuse QR= 17 cm, and OR= 15 cm, ( since PR = 30 cm , it divides into two)

QR^2 = OR^2 + OQ^2

(17)^2 = (15)^2 + OQ^2

289 = 225+OQ^2

289-225= OQ^2

64= OQ^2

OQ= 8cm

Therefore, QS= OQ + OS

                       = 8+8

                       =16cm

Hope it helps!!!!!!!!!!!