perimeter of semi-circular ground is 17.5cm
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Given radius(r)=217.5m and width of the path(w)=2m
Area of path=π(R2−r2)
R=r+ω=217.5+2=10.75m
∴Area=3.14(10.752−8.752)=122.46m2
Cost of construction = Rs. (122.46×25) = Rs. 3061.5
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