Perimeter of the base of a solid hemisphere is 8πcm. Find its T.S.A
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Answer:
32π/3=10.66π
Step-by-step explanation:
2πr=8π
2r=8
r=4
TSA=2πR^2/3
TSA=2*π*4*4/3
TSA=32π/3
TSA=10.66π
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