perimeter of the base of a solid hemisphere is 8pie cm .find uts TSA
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so, the solid is cylinder, since the perimeter of base is in terms of pie.
so first we will find radius
perimeter (circle) = 2πr
8π. = 2πr
8π/2π. = r
4 = r
TSA = π r^2 h
= π 4^2 h
= 16πh
so the height is not specified, so i leave it as it is
now please mark me as brainlist
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