Question

Perimeter of the floor of the rectangle hall is 34m and height 3m find the area of four walls

Answer 1

Answer:

Perimeter=2(l+b)

34=2(3+b)

34=6+2b

34-6=2b

28=2b

b=14

A(four walls)=4lb

=4×3×14

=168

Answer 2

Answer:

102m^2

Step-by-step explanation:

Height of floor = 3m

Perimeter of floor = 34m

So, perimeter = 34

2(l+b) = 34

l+b = 34/2

l+b = 17m

∴ Area of four walls of room = 2 (lh + bh) m^2

= 2h (l+b)

= 2 (3) (17)

= 102m^2