perimeter of the rectangle is 48 cm and its width is 9 cm.calculate its area
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Answered by
2
Perimeter of a rectangle = 2(l+b)
breadth = 9cm
2(l+9) = 48
2l + 18 = 48
2l = 48 - 18
2l = 30
l = 15cm
length = 15 cm
area = l * b
= 15 * 9
= 135 cm^2
breadth = 9cm
2(l+9) = 48
2l + 18 = 48
2l = 48 - 18
2l = 30
l = 15cm
length = 15 cm
area = l * b
= 15 * 9
= 135 cm^2
Answered by
0
Given that
perimeter of rectangle =48 cm
width of rectangle =9cm
perimeter of rectangle =48 cm
2(l+b) = 48
2 (l+9)= 48
2l + 18 = 48
2l= 48-18
2l= 30
l=15
Area of rectangle = l×b
=15× 9
= 135
perimeter of rectangle =48 cm
width of rectangle =9cm
perimeter of rectangle =48 cm
2(l+b) = 48
2 (l+9)= 48
2l + 18 = 48
2l= 48-18
2l= 30
l=15
Area of rectangle = l×b
=15× 9
= 135
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