Question

perimeter of the Rhombus is 100 M and its diagonal is 40 m find the area of Rhombus

Answer 1

Perimeter of rhombus=4*side

So side=25m

And we know that in a rhombus diagonal divides rhombus in two eauilateral triangle.

Area of one triangle:- s=(25+25+40)/2 =45

So area=
$\sqrt{(s(s-a)(s-b)(s-c)}$
$\sqrt{45(45-40)(45-25)(45-25))}$
= 300m^2

So total area is 300*2=600m^2

Answer 2

perimeter=100 m

we know that the sides of the diagonal are equal

therefore

each side

=100/4

=25 m

the other diagonal

=√25²-20²*2

=√625-400*2

=√225*2

=15*2

therefore area =1/2*30*40

=15*40

=600 m²(answer)