Question

Perimeter of the rhombus is 100 m and its diagonal is 40m. Find the area of rhombus.

Answer 1

perimeter=100 m

we know that the sides of the diagonal are equal

therefore

each side

=100/4

=25 m

the other diagonal

=√25²-20²*2

=√625-400*2

=√225*2

=15*2

therefore area =1/2*30*40

=15*40

=600 m²(answer)

Answer 2

HELLO
HERE IS YOUR ANSWERRRR....
RHOMBUS HAS EQUAL SIDES . OK
SO , EACH SIDE OF RHOMBUS IS 100/4 = 25M
.....
~DIAGONAL= 40m~
THAT WAS GIVEN

NOW DRAW OTHER DIAGONAL , EACH DIAGONAL IN A RHOMBUS BISECTS THE OTHR DIAGONAL .
SO , HALF OF FIRST DIAGONAL = 20M

*BY PYTHAGORAS THEORAM*,
(HALF OF OTHER DIAGONAL )^2 = SQAURE OF ONE SIDE - SQUARE OF HALF OF OTHER DIAGONAL
HALF OF OTHER DIAGONAL = √25^2-20^2
= 15M
OTHER DIAGONAL = 2 × HALF OF DIAGONAL =2×15m = 30m
AREA OF A RHOMBUS = 1/2× DIAGONAL × DIAGONAL = 1/2×30×40= 600M^2

I hope this answer helps you . Thank you and have a nice day