perimeter of the semicircle is 144m find the area
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Answer :-
→The perimeter of semicircle is 144 cm
→which is equal to 2r + (π)r
→where r= radius
→2r + (π)r = r(14+22)/7 = r(36/7)
→so r = 144*7/36 = 28 cm
The area of the semicircle is = (22/7)*28^2/2 = 1232 sq cm.
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Answer:
- 2=%&" n ute Dvorak
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