perimeter of trapezium is 52 centimetre and its each non parallel sides is equal to 10 cm and height is 8 cm find the area of the trapezium
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5
the area of trapezium is 128 square cm
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Answered by
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let the two parallel sides are x and y
then perimeter=10+10+x+y
52=20+x+y
52-20=x+y
32=x+y
the area of trapezium=1/2 ×(sum of parallel side)×height
we have the sum of parallel side=32
then
area,
1/2×32×8
=128cm^2
then perimeter=10+10+x+y
52=20+x+y
52-20=x+y
32=x+y
the area of trapezium=1/2 ×(sum of parallel side)×height
we have the sum of parallel side=32
then
area,
1/2×32×8
=128cm^2
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