Perimeter of triangle 32cm.one aide of its side is equal to 11cm and the difference of the other two is 5cm
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Let the three sides of the triangle is a, b, c
a+b+c=32
Given one side is 11cm
a=11cm
And difference of other two is b-c=5
b=c+5
11+c+5+c=32
2c=16
c=8
b=8+5=13
So a=11cm,b=13cm,c=8cm
a+b+c=32
Given one side is 11cm
a=11cm
And difference of other two is b-c=5
b=c+5
11+c+5+c=32
2c=16
c=8
b=8+5=13
So a=11cm,b=13cm,c=8cm
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