perimeter of triangle abc is 72 & DEF as the midpoint find perimeter of triangle DEF
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In triangle ABC,
DF = 1/2 BC (Mid-Point theorem) .......(1)
Similarly,
DE = 1/2 AC ......(2)
EF = 1/2 AB ......(3)
Perimeter of triangle ABC = AB + BC + AC
1/2 AB + 1/2 BC + 1/2 AC = 1/2 perimeter of triangle ABC
DE + DF + EF = 1/2 ABC = 36 ........(from 1,2 and 3)
DE + DF + EF = DEF = 36
DF = 1/2 BC (Mid-Point theorem) .......(1)
Similarly,
DE = 1/2 AC ......(2)
EF = 1/2 AB ......(3)
Perimeter of triangle ABC = AB + BC + AC
1/2 AB + 1/2 BC + 1/2 AC = 1/2 perimeter of triangle ABC
DE + DF + EF = 1/2 ABC = 36 ........(from 1,2 and 3)
DE + DF + EF = DEF = 36
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