perimeter of triangle field is 240 dm if 2 sides of it are 78dm and 50dm find the length of the perpendicular on the side of length 50dm from the opposite vertex
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let the length of perpendicular be y dm
by Pythagoras theorem ,
78 ×78=50×50+y×y
by Pythagoras theorem ,
78 ×78=50×50+y×y
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