Question

perimeter of triangle is 48 one side is 21 find shortest side​

Answer 1

Answer:

a + b + c = 48

Let a = 21,

b = 48 -a-c = 48 -21-c = 27 -c

b-3 = 24-c.

Area A = √ { s(s-a)(s-b)(s-c) } &

s =(a+b+c)/2 =24

Area A = √ { 24(24–21)(24-b)(24-c)}

Area A = √ { 24(24–21)(24-b)(b-3).

Area A = √ { 72(24-b)(b-3)}

Area A =6 √ { 2(24-b)(b-3)}

For A to be an integer, 24 -b must be = 2(b-3)

Or b = 10

Step-by-step explanation: