Question

Perimeter of triangle is 6 x square - 4 x + 9 and 2 sides are axis square - 2 x + 1 and 3 x square - 5 x + 3 find the third side of triangle

Answer 1

Answer:

2x² +2x +5

Step-by-step explanation:

Given that,

Perimeter of a triangle = 6x² - 4x +9

Side length of squares = x² -2x+ 1 , 3x² -5x +3

let the third be x

Now,

Perimeter = Add all the sides of a triangle

6x² -4x +9 = x² -2x +1 +3x² -5x +3 + x

6x² -4x +9 = 4x² - 6x + 4

6x² -4x² -4x +6x +9 -4= 0

2x² +2x +5 =0

Answer 2

Answer:

Third side of ∆ is 2x²+ 2x + 5 = 0

or

name of this ∆ is scalene triangle.

Step-by-step explanation:

Given data:-

Perimeter of ∆ :- 6x²-4x+9

two sides of given ∆ are :-

(i). x²-2x+1

(ii). 3x²-5x+3

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.

let 3rd side of our given ∆ is " x ".

.

.

as we know that:-

perimeter of any ∆ = sum of all side's

6x²-4x+9 = (i) side + (ii) side + (iii) side

6x²-4x+9 = { x²-2x+1 } + { 3x²-5x+3 } + { x }

6x²-4x+9 = x²-2x+1+3x²-5x+3+x

6x²-4x+9 = 4x²-7x+4+x

6x²-4x+9 = 4x²-6x+4

6x²-4x+9-4x²+6x-4 = 0

2x²+ 2x + 5 = 0