Question

perimeter of triangle is 7x^2-17xy+5y^2+8
and two sides are 4x^2-7xy+4y^2-3 and
6y^2-8xy+x^2​

Answer 1

Answer:

7x^2-17xy+5y^2+8 = (4x^2-7xy+4y^2-3 )+ ( 6y^2-8xy+x^2)+ thirdside

2x^2-2xy-5y^2+11 = thirdside

Answer 2

Answer:

2x² - 2xy - 5y² + 11.

Hope Answer is correct