Question

Perimeter of triangle whose coordinates are(-3;0)(3;0)(0;4)

Answer 1

Answer:

❣ ANSWER ❣

✡ ROCKY HERE ✌

By using distance formula ;

$ab = \sqrt{ {(x1 - x2)}^{2} + {(y1 - y2)}^{2} } \\ ab = \sqrt{( 3 + 3) {}^{2} + (0 - 0) {}^{2} } \\ ab = \sqrt{36 + 0} \\ ab = 6$

ab = 6 units

$bc = \sqrt{ {(3 - 0)}^{2} + (4 - 0) {}^{2} } \\ bc = \sqrt{9 + 16} \\ bc = \sqrt{25} \\ bc = 5$

bc = 5 units

$ac = \sqrt{ {(0 + 3)}^{2} + {(4 - 0)}^{2} } \\ ac = \sqrt{9 + 16} \\ ac = \sqrt{25} \\ ac = 5$

ac = 5 units

ac + ab + bc

= 5 + 6 + 5

= 16 units

perimeter = 16 units

✴HAPPY TO HELP