perimeter of two squares are 52m and 326m. find the length of the side of the square whose area is equal to the sum of the areas of the two squares
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Answered by
12
Square 1=52m(perimeter)
Therefore ...side=52/4=13cm
Area=side×side=13×13=169
Square 2=326m(perimeter)
Therefore side=81.5cm
Area=side×side=81.5×81.5=66,422.5
Now...area of bigger square=66,422.5+169
=66,591.5
Side of bigger square=(66,591.5)^1/2
=258 m
@skb
Therefore ...side=52/4=13cm
Area=side×side=13×13=169
Square 2=326m(perimeter)
Therefore side=81.5cm
Area=side×side=81.5×81.5=66,422.5
Now...area of bigger square=66,422.5+169
=66,591.5
Side of bigger square=(66,591.5)^1/2
=258 m
@skb
angelshah:
Can u explain me
Answered by
20
Find the length of the first square;
Perimeter = 4 x Length
52 = 4 x Length
Length = 52 ÷ 4
Length = 13 cm
Find the area of the first square:
Area = Length x Length
Area = 13 x 13
Area = 169 cm²
Find the length of the second square:
Perimeter = 4 x Length
326 = 4 x Length
Length 326 ÷ 4 = 81.5 cm
Find the area of the second square:
Area = Length x Length
Area = 81.5 x 81.5
Area = 6642.25 cm²
Find the sum of the two area:
Total area = 169 + 6642.25 = 6811.25 m²
Find the length of the new square:
Area = Length x Length
Length² = 6811.25 m²
Length = √ 6811.25
Length = 82.53 cm
Answer: The length is 82.53 cm
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