Question

Perimeter of two squares are 748 cm and 336 and find the perimeter of the square whose area is equal to the sum of areas of the to square

Answer 1

sides of two squares are
$748 \div 4 = 187$ and 336÷4=84 respectively
sum of areas is 187 ×187 +84×84=34969+7056=√42025
the side of square is 205
perimetet is 820

Answer 2

$\huge \underline \bold{QUESTION}$

The perimeter of one square is 748 cm and that of another square is 336 cm. Find the perimeter of a square which is equal in area of the sum of the two square.

☞ Answer :

Perimeter of the required square = 820 cm.

☞ Given :

Perimeter of square (1) = 748 cm.

Perimeter of square (2) = 336 cm.

☞ To Find :

Perimeter of the required square (3).

☛ How To Find :

We know,

Side of square = Perimeter/4

∴ Side of square (1) = 748/4 = 187 cm.

∴ Area of square (1) = (side)² = (187)² =

34969 cm²

Side of square (2) = 336/4 = 84 cm.

∴ Area of another square = (84)² = 7056 cm²

Now, sum of areas of squares = 34969 + 7056

= 42025 cm²

Again, area of square(3) = sum of areas of squares (1) & (2)

= 42025 cm²

∴ Side of third square =$\sqrt{42025}$

42025 = 205 cm

∴Perimeter of square (3) = 4 × side of square (3)

= 4 × 205 = 820 cm

∴ Perimeter of the required square = 820 cm.