Question

Perimeter oftriangle who sides are: 5/2,11/4,18/5.

Answer 1

Perimeter of Triangle = Sum of all sides

= 5/2 + 11/4 + 18/5

= (50 + 55 + 72) / 20

= 177 / 20

=> Perimeter = 8.85 cm........●

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Hope it was helpful.

Answer 2

Answer:

Required perimeter is 8.85 unit.

Step-by-step explanation:

Given,

Three sides of a triangle are $\frac{5}{2} , \frac{11}{4} , \frac{18}{5}$

Here we want to find perimeter of the triangle.

But now question is how can we find perimeter of a triangle?

We know,

If sides of a triangle are x unit,y unit and z unit then perimeter will be $(x + y + z) \: unit$

For example,

Sides of a triangle are 2 m ,3 m and 5 m

Then perimeter is

$(2 + 3 + 5) \: m \\ =( 5 + 5) \: m \\ = 10 \: m$

Here given sides are $\frac{5}{2} , \frac{11}{4} , \frac{18}{5}$

Required perimeter is

$\frac{5}{2} + \frac{11}{4} + \frac{18}{5} \\ = \frac{5 \times 10 + 11 \times 5 + 18 \times 4}{20} \\ = \frac{50 + 55 + 72}{20} \\ = \frac{177}{20} \\ = 8.85 \: unit$

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