Question

perimeter pf a semicircle is 108cm . what is the area of the semicircle

Answer 1

Answer:

682 sq cm

Step-by-step explanation:

The perimeter = (pi)r + 2r where r is the radius. Here

r[(22/7) + 2] = 108, or

r = 108/[(22/7) + 2] = 21

So the area of the semicircle is (pi)*(21^2)/2 = 693 sq cm

Answer 2

perimeter = pi x r + 2r = r (pi+2)

=108

r x (22/7+2)

r x (36/7) = 108

r = 21cm

area = pi x r^2/2

= 22/7 x 21^2/2

= 11*21*3

= 693 cm^2