Question

Perimeters of two similar triangles are 30 cm and
20 cm respectively. If one side of first triangle is 12 cm, then
find the length of corresponding side of the other trianale
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Answer 1

Here is your answer
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The perimeter of two similar triangles are 30cm and 20cm respectively, if one side of first triangle is 12cm, determine the corresponding side of the triangle?

We know, a/d = b/e = c/f = (a+b+c) / (d+e+f)

Therefore, for two similar triangles, if a, b & c are sides of the first triangle and d, e & f are corresponding sides of the second triangle then ratio of corresponding sides of the two similar triangles is equal to ratio of their perimeter.

Now, one side of the first triangle =12cm

Let the corresponding side of the second triangle =x

Also, perimeter of the first triangle =30cm

& perimeter of the second triangle =20cm

Therefore, 12/x =30/20

=> x = (12*20) / 30 =8cm
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Answer 2

RULE:
In similar triangles the ratio of their perimeter is equal to the ratio of their corresponding sides

Let the unknown value be 'x'

30:20 =12:x

30/20 =12/x

30x = 12*20

30x = 240

x = 240/30

x = 8cm

hence the corresponding side is 8cm

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