Question

perimetet of a rhombus is 40 cm and one of its diagonal is 16 cm find area of Rhombus for 9 class

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Answer 1

Answer:

here is your answer....

Step-by-step explanation:

according to the question

perimeter of a rhombus is  40cm

one of its diagonal is 16cm

now, p=side x 4

40=side x 4

side=40/4=10

thus, side = 10 ;

now as rhombus is a quadrilateral it diagonal bisect at right angle so we get,

half diagonal = 16/2=8;

thus, $10^{2}$=$8^{2}$+$x^{2}$

$x^{2}$=$\sqrt{36}$=6

area =1/2 of (product of diGONALS)

1/2 X 16 X 12

= 96 sq.cm^2