Question

Period of 2 sin*3x -3 cos*3x is
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Answer 1

Answer:

2pi

Step-by-step explanation:

let consider the equation as f(x) =2sin*3x-3cos*3x

let k be the period of f(x)

then f(x + k) = f(x)

now substitute 2π in the place of k

then 2 (sin(x+2π))^3 - 3(cos(x+2π))^3 =

2π+thetha in first quadrant so sin and cos function are positive.

so 2(sin(x+2pi))*3= 2sin*3x

similarly 3(cos(x+2pi))*3=3cos*3x

therefore 2π is a period of f(x)