period of cos(x+2x+3x+........+nx)is
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Given: The trigonometric term cos(x+2x+3x+........+nx)
To find: Period of the given term.
Solution:
- Now we have given the term:
f(x) = cos(x+2x+3x+........+nx)
- Now we know that ∑ r = n(n+1)/2 (∑ from r = 0 to r = n)
- We can rewrite it as:
cos(n(n+1)/2 × x)
cos(xn(n+1)/2)
- Now we know that the period of cos x is 2π.
- Then period of f(x) will be:
2π x (2/n(n+1))
Answer:
So the period of given term is: 4π//n(n+1)
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