Question

period of oscillation of a simple pendulum is measured in an experiment to be 2.01s, 2.03s, 1.99s, 1.98s, 2.05s and 2.04s. find the absolute errors and percentage error in the measurement​

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:

Hence, the original number is 10x + y (Assuming x to be the ten's digit and y to be the one's digit)

After interchanging the digits the new number will be 10y + x (After reversing, y becomes the ten's digit and x becomes the one's digit)

Condition 1: Sum of the digits is 9 ⇒ x + y = 9     --------- equation (i)

Condition 2: The number obtained by interchanging the digits is 27 greater than the earlier number.

⇒ New number = 27 + original number

⇒ 10y + x = 27 + (10x + y)

⇒ 10y + x = 27 + 10x + y

⇒ 10y - y + x - 10x = 27

⇒ 9y - 9x = 27

⇒ y - x = 3    -------- equation (ii)

By adding equation(i) and equation(ii):

x + y + y - x = 9 + 3

⇒ 2y =  12

⇒ y = 6

From equation(i): x + 6 = 9 

⇒ x = 9 - 6 = 3

⇒ x = 3 and y = 6

⇒ The required number is 10x + y = 10 × 3 + 6 = 30 + 6 = 36

Thus, the required two-digit number is 36.

(ii)

⇒ New number = 27 + original number⇒ 10y + x = 27 + (10x + y)⇒ 10y + x = 27 + 10x + y⇒ 10y - y + x - 10x = 27⇒ 9y - 9x = 27⇒ y - x = 3