Question

period of |sinx| -|cosx|​

Answer 1

Answer:

Hi

It’s “pi ( π )”

Step-by-step explanation:sinx - cosx: which is a two function involved question into a single function involved question so as to make it easy to solve and manipulate...

1. Multiply and divide this function by sqrt(2) : sqrt[2]( sinx/(sqrt(2)))-(cosx/(sqrt(2)))

2. Now you may write it as: sqrt(2)sin(x-45°)

3. Draw the graph of sin(x-45°)

4. It’s period will be 360°

5. If you take modulus as: |sin(x-45°)| It’s period will now be 180°(pie)

6. Multiplying by the constant like sqrt(2) will certainly not affect it’s period.

7. Hence the period of the function comes out to be 180° or pie

hope you understood