Math, asked by hari1126, 10 months ago

Period of the function is sin[3x]cos[3x]-cos3xsin[3x]

Answers

Answered by Sachinarjun

0

Step-by-step explanation:

period of sin theta and cos theta =2π

Therefore,. the period of sin3x cos3x-cos3xsin3x=2π×2π-2π×2π=0

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