Question

periodicity of 3.1232323​

Answer 1

Given : 3.1232323​..

To Find : periodicity

Solution:

3.1232323​..

= $3.1\overline{23}$

23 is being repeated    

Hence 23 is the period

and it has 2 digits

hence 2 is the periodicity

N = $3.1\overline{23}$

10N = $31.\overline{23}$

1000N = $3123.\overline{23}$

=> 990N  = 3092

=> N = 3092/990

=> N = 1546/495

3.1232323​  = 1546/495

2 is the periodicity

Learn More:

The period of 1/3 and 4/3 and periodicity of 3/7 and 4/3

brainly.in/question/16288010

find the period of decimal of 22/7 and the length of its period ...

brainly.in/question/4267196