Question

Permutation and combination...if a batsman scores 12 runs in an over in how many ways. N he score it (repetition is allowed)

Answer 1

Answer:

Step-by-step explanation:

You can see that 3 6's are much needed to get a sum of 30 in 6 balls

So we are left with 3 balls and 12 runs

This can be done by following ways

6,6,0 or 6,4,2 or 4,4,4 or 6,3,3

So total possibility of the over is

6,6,6,6,6,0

6,6,6,6,4,2

6,6,6,4,4,4

6,6,6,6,3,3

And now you have to finf unique sequences which is equivalent to say you have to permutate these overs

For 1st permutation is given by 6!5!=6

For 2nd permutation is given by 6!4!=30

For 3rd permutation is given by 6!3!3!=20

For 4th permutation is given by 6!4!2!=15

Total sequences=6+30+20+15=71

So 71 should be the desired answer