perpendicular bisector of a trapezium
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Let AD∩BC={E} and EN be a median of ΔDEC.
Thus, since ∡EDC=∡ECD, we obtain that ED=EC and from here EN is an altitude of ΔDEC.
Also, since ∡EAB=∡EBA, we obtain that EA=EB and since EN⊥AB,
we see that EN is a perpendicular bisector of AB and we are done!
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