Question

Perpendicular distance from (0,0) of line 5x+12y_7 is

Answer 1

Step-by-step explanation:

given O = (0,0)

equation is

$5x + 12y - 7 = 0$

perpendicular distance from a (x,y) point to the straight line ax+by+c=0 is

$\frac{(ax + by + c)}{ \sqrt{{a}^{2} + {b}^{2}} }$

substitute x=0, y=0, a=5, b=12, c=-7 in the above formula

$\frac{0x + 0y - 7}{\sqrt{ {5}^{2} + {12}^{2} } }$

$= \frac{ - 7}{\sqrt{25 + 144}}$

$= \frac{ - 7}{ \sqrt{196} }$

$= \frac{ - 7}{14}$

distance cannot be nagative actually modless is there in bracket so iam replacing -7 to 7

$= \frac{1}{2} units$