Perpendicular distance from origin to the line 3x+4y−12=0 is
Answers
Answered by
0
Answer:
12/5
Step-by-step explanation:
We Know That ,
Perpendicular Distance From a point (x1 , y1) + 0
Here,
(x1 , y1) = (0,0)
ax + by + c = 3x + 4y - 12
So,
Perpendicular Distance = 3(0)+4(0) - 12/√3^2+4^2
= 0 + 0 - 12 /√9+16
= -12/√25 = 12/5 units
Answered by
0
Step-by-step explanation:
find the RF for scale 1cm=2.5km
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