Question

Perpendicular distance of (2,-3,6) from 3x-6y+2z+10=0 is........,Select the correct option from the given options.
(a) 13/7
(b) 46/7
(c) 7
(d) 10/7

Answer 1

for solution refer attachment option b is correct

Answer 2

concepts :- perpendicular distance of $\{x_1,y_1,z_1\}$ from ax + by + cz + d = 0 is given by $\frac{|ax_1+by_1+cz_1+d|}{\sqrt{a^2+b^2+c^2}}$

here, a = 3, b = -6 and c = 2 and point (2, -3, 6)
so, perpendicular distance = |3 × 2 - 6 × -3 + 2 × 6 + 10|/√{3² + (-6)² + 2²}

= |6 + 18 + 12 + 10|/√(9 + 36 + 4)}

= 46/7

hence, option (b) is correct.