Question

perpendicular distance of the origin from straight line 3x-4y-25=0 ​

Answer 1

Answer:

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Step-by-step explanation:

$so \: given \: line \: is \: 3x - 4y - 25 = 0 \\ comparing \: it \: with \\ \: ax + by + c = 0 \\ \\ we \: get \\ a = 3 \: , \: b = - 4 \: , \: c = - 25 \\ \\ so \: we \: know \: that \\ perpendicular \: distance \: from \: origin \\ is \: given \: by \\ \\ | \: \frac{c}{ \sqrt{a {}^{2} + b {}^{2} } } \: | \\ \\ = | \: \frac{ - 25}{ \sqrt{(3) {}^{2} + ( - 4) {}^{2} } } \: | \\ \\ = | \: \frac{ (- 25)}{9 + 16} \: | \\ \\ = | \frac{ - 25}{25} | \\ \\ = | - 1| \\ \\ = 1 \: unit$