perpendicular distances between the pair of opposite sides of parallelogram are 3cm and 4cm and one angle is 60 degree using ruler and compass only ,construct parallelogram
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I is not possible for me to construct it on this brainy on paper it is easy
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Steps of construction:
(i) Draw a straight-line PQ, take a point A on it.
(ii) At A, construct ∠QAF = 60o
(iii) At A, draw AE ⊥ PQ from AE cut off AN = 3cm
(iv) Through N draw a straight line to PQ to meet AF at D.
(v) At D, draw AG ⊥ AD, from AG cut off AM = 4cm
(vi) Through M, draw at straight line parallel to AD to meet AQ in B and ND in C.
Then, ABCD is the required parallelogram
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