Perpendicular drawn on a line segment at a given point on it. ( note- answer only if you no) pls answer this dont be spam or i will report you. plz help me
Answers
Answer:
Step-by-step explanation:
Construction Draw two intersecting lines passing through the point P and which is perpendicular to l
To prove Only one perpendicular line can be drawn through a given point i.e., to prove ∠P=0∘.
proof In ΔAPB, ∠A+∠P+∠B=180∘ [by angle sum property of a triangle is 180∘]
⇒ 90∘+∠+90∘=180∘
⇒ ∠P=180∘−180∘
∴ ∠P=0∘
So, lines m and m coincide.
Hence, only one perpendicular line can be drawn through a given point.
-Construction Draw two intersecting lines passing through the point P and which is perpendicular to I
To prove Only one perpendicular line can be drawn through a given point i.e., to prove ZP=0°.
proof In AAPB, ZA+ZP+ZB=180• [by angle sum property of a triangle is 1800]
» 900+Z+900=1800
→ ZP=1800-180•
.: ZP=0°
So, lines m and m coincide.
Hence, only one perpendicular line can be drawn through a given point.